Question

there are 2 complex numbers z & z' . if z=5+3i and zz'=3-4i so gain the value of z' in the form of a+ib ?

Answer 1

Suppose that z'=a+ib, i=√-1, and z=5+3i, zz'=3-4i.
(a+ib)(5+3i)=3-4i → (5a-3b) + i(3a+5b) = 3 - i4.
Equate real and imaginary parts, 5a-3b=3 and 3a+5b=-4.
Solving this you get a=3/34, b=-29/34.

Answer 2

Answer:

a=3/34 and b=-29/34

Step-by-step explanation: