There are 2 containers, with one containing 4 red and 3 green pencils and the other containing 3 blue and 4 green pencils. One pencil is drawn at randon from each. The probability one is red and other is blue
Answers
Answer:
1/2
Step-by-step explanation:
Total number of outcomes= 14
Number of favoured outcomes= 7
Therefore, probability= 7÷14
= 1/2
12/49 is probability that one is red and other is blue
Step-by-step explanation:
Container 1 :
4 Red Pencil
3 Green Pencils
Total = 7 Pencils
Probability of Red pencils from Container 1 = 4/7
Probability of Green pencils from Container 1 = 3/7
Probability of Blue Pencils from Container 1 = 0
Container 2 :
3 Blue Pencil
4 Green Pencils
Total = 7 Pencils
Probability of Blue pencils from Container 2= 3/7
Probability of Green pencils from Container 2 = 4/7
Probability of Red Pencils from Container 2 = 0
probability one is red and other is blue
Red pencils from Container 1 & Blue pencils from Container 2
= (4/7)(3/7)
= 12/49
12/49 is probability that one is red and other is blue
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