Question

There are 2 drums, mixtures A&B in each.
In drum 1, A:B = 18:7.
The two drums are mixed into a Drum 3 in 3:4 ratio.
The resultant ratio is 13:7
Find ratio of A:B in Drum 2
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Answer 1

Let in drum 2, A and B are in the ratio m : n.

Given, In drum 1, A and B were in the ratio 18 : 7 = 18x : 7x .

Final mixtures ratio of contribution of drum 1 and drum 2 = 3: 4 = 75x : 100x

So A in final mixture = 18x × 3+100x × m/(m+n) = ( 154m+54n)/(m+n) x

B in final mixture = 7x × 3+100x × n/(m+n) = ( 21m+121n)/(m+n) x

Given A : B in final mixture = 13:7

Or (154m+54n )/(21m+121n )=13/7

1078m+378n=273m+1573n

805m=1195n

m:n=1195∶805=239∶161

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Answer 2

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