Question

There are 2 red, 2 white and 2 green balls in a bag. One ball is drawn at random. C is the event that

the ball is not green​

Answer 1

Answer:

Step-by-step explanation:

Ω = {R,R,W,W,G,G} = 6

Favorable events (Ball is not green) = {R,R,W,W} = 4

p(C) = 4/6 = 2/3 = 0.66666

Answer 2

Answer:

P(C) = ⅔

Step-by-step explanation:

$probability \: = \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes} \\ p(c) = \frac{2 + 2}{2 + 2 + 2} \\ \: \: \: \: \: \: \: \: \: = \frac{4}{6} = \frac{2}{3}$