There are 2 red, 3 blue and 5 black balls in a bag. A ball is drawn from the bag without looking in to the bag. What is the probability of getting a non-blue ball? (a) 3/5 (b) 7/10 (c) 2/5 (d) 6/10
Answers
Answer:
No of red balls are 2.
The probability of getting a red ball is no of favorable outcomes/total outcomes.
Here
Total out comes are=2+3+5=10
So
Probability getting a ball is = 2/10=1/5
Answer:
7/10
Step-by-step explanation:
Method 1
We want non-blue balls, it means we want red and black balls.
∴ P = (no. of red & black balls)/total balls
⇒ P = (2 + 5)/(2 + 3 + 5)
= 7/10
Hence the probability of getting a non-blue ball is 7/10.
Method 2
We want the probability of getting a non-blue ball, if probability of getting a ball is P(A), then probability of not getting a blue ball is 1 - P(A).
P(A) = 3/10
Probability of getting a non-blue ball = 1 - P(A)
= 1 - 3/10
= 7/10