There are 2 red and 3 black balls in a bag. 3 balls are taken out at random from the
bag then the probability of getting 2 red and 1 black ball or 1 red
and 2 black ball is
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Answer:
- total balls = 2 red + 3 balck = 5
- section of 3 ball = 5C3 = 10
☞1 st situation = 2C2 × 3C1 = 3/10
☞2nd situation = 2C1 × 3C2 = 6/10
☞probability = 3+6/10 = 9/10 = 0.9
✯ Hope its helping ✯
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