Question

There are :
2 red balls, 3 green balls, 7 blue balls in a bag.

If 4 balls are picked then what is probability of happening of event in which
1st ball is blue, 2nd ball is red, 3rd ball is green and 4th ball is red?​​

Answer 1

Correct option is

B

2/10

Total number of balls =2+3+5=10

Number of red balls=2

P(A)=

Total Number of possible outcomes

Number of favorable outcomes

∴P(A)=

10

2

Answer 2

Step-by-step explanation:

correct answer is =2+3+5=10