Question

there are 2 ropes 48m and 72m in length respectively. if they are cut into equal pieces what will be the maximum length of each equal piece

Answer 1

maximum length of each equal piece = 24 m

Step-by-step explanation:

2 ropes 48m and 72m in length

to find maximum length of each equal piece

We need to find HCF ( Highest Common Factor) of 48 & 72

48 = 2 * 2 * 2 * 2 * 3

72 =2 * 2 * 2 * 3  *  3

Common Fcators are 2 , 2 , 2 & 3

HCF = 2 * 2 * 2 * 3 = 24

maximum length of each equal piece = 24 m

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Answer 2

24 cm

Step-by-step explanation:

Length of Rope 1 = 48 m

Length of Rope 2 = 72 m

We are supposed to find  if they are cut into equal pieces what will be the maximum length of each equal piece

So, We will use HCF

2 | 48        2 | 72

2 | 24        2 | 36

2 | 12         2 | 18

2 | 6          3 |  9

3 | 3          3 |  3

  |  1            |   1

$48 = 2  \times 2 \times 2 \times 2 \times 3$

$72= 2  \times 2 \times 2 \times 3 \times 3$

$HCF= 24$

Hence the maximum length of each equal piece is 24

#Learn More :

HCF

1)https://brainly.in/question/3803222, Answered by Atalante