Question

there are 2 triangles of same or equal base .A ratio of areas of triangle A(∆first) = 6. ,A(∆second)=5 ,height first =9 and find height second​

Answer 1

Answer:

area of a triangle=(1/2)×b×h

here, area 1 : area 2 = h1 : h2

or, 6:5=9:h2

or, h2 = 6×9/5 = 54/5

Answer 2

Answer:

7.5 cm

Step-by-step explanation:

Let A1 and A2 be the areas of two triangles.

A1>A2

A1=[(1/2) b1 * h1] and A2=[(1/2) b2 * h2]

Now, accordingly

6/5 = b1 * h1 / b2 * h2

As the base is same so:-

h1 / h2 = 6/5

h2= 9* 5/6

h2 = 45/6 cm

h2 =7.5 cm

Hence the height of second triangle is 7.5 cm