Question

There are 2 types of mixed nuts. Type a and type b. 1/3rd of type a nuts and 2/5th of type b nuts are peanuts. A mixture of 2 1/2kg of type a and 5 1/2 kg of type b are mixed together what fraction of this mixture is peanut

Answer 1

Given:

Peanuts in:

$\implies$ Type A = 1/3

$\implies$ Type B = 2/5

Now:

We have: 5/2 kg of Type A nuts

Total peanuts in Type A:

$\implies$ 5/2 × 1/3

$\implies$ 5/6 kg

We have: 11/2 kg of Type B nuts

Total peanuts in Type B:

$\implies$ 11/2 × 2/5

$\implies$ 11/5 kg

Total wait of both:

$\implies$ 5/2 + 11/2

$\implies$ 16/2

$\implies$ 8 kg

And:

Weight of peanuts in both:

$\implies$ 5/6 + 11/5

$\implies$ (25 + 66) / 30

$\implies$ 91/30

So:

Fraction of peanuts in this mixture:

$\implies$ 91/(30 × 8)

$\implies$ 91/240

Answer 2

Step-by-step explanation:

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