there are 2 vessels which are filled with milk of 2 qualities worth rs.10 per litre and rs.11 per litre. in what approximation ratio these two be mixed to get a new quality of milk of worth rs.10.67 per litre?
Answers
Cost Price(CP) of Type 1 milk is Rs. 10 per litre
Cost Price(CP) of Type 2 milk is Rs. 11 per litre
Let Type 1 and Type 2 are mixed in the ratio of a : b.
Therefore,
We can write it as: (10a + 11b)/(a + b) = 10.67 = 1067/100.
Now let's assume two equations:
10a + 10b = 1067 ----------- (i)
a + b = 100. ----------- (ii)
Multiplying the equ (ii) by 10 we get,
10a + 10b = 1000 ----------(iii)
By (i) - (iii) we get,
b = 67.
Putting the value of b in equ (ii) we get, a = 33.
Therefore, ratio = 33 : 67 (Ans)
Answer:
Required Ratio of milks is is 33 : 67
Step-by-step explanation:
To find: Ratio of milk of both quantities so that cost of mixture per liter is Rs. 10.67
let x be the Quantity of the milk whose worth is Rs. 10.
y be the Quantity of the milk whose worth is Rs. 11.
According to the question,
10x + 11y = 10.67( x + y )
10x + 11y = 10.67x + 10.67y
11y - 10.67y = 10.67x - 10x
0.33y = 0.67x
y/x = 0.67/0.33
y/x = 67/33
x/y = 33/67
Therefore, Required Ratio of milks is 33 : 67