Question

There are 20 cylindrical pillars in a building each having diameter of 50cm and height 4m

Answer 1

Answer:

It is given that

Diameter of one pillar =50cm=0.5m

So the radius of one pillar =0.5/2=0.25m

Height of one pillar =4m

We know that

Lateral surface area of one pillar =2 πrh

By substituting the values

Lateral surface area of one pillar =2×(22/7)×0.25×4

So we get

Lateral surface area of one pillar =6.85 m

2

So the lateral surface area of 20 pillars =20×6.285=125.714 m

2

It is given that the cost of cleaning =Rs.14 per m

2

So the cost of cleaning 125.714 m

2

=Rs.(14×125.714)

We get

Cost of cleaning 125.714 m

2

=1760

Therefore, the cost of cleaning 125.714 m

2

is Rs.1760

Step-by-step explanation:

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