There are 20 cylindrical pillars in a building each having a diameter of
50cm and henght 4 m. Find the cost of cleaning them at 14
The curved surface area of a right circular cylinder is 44 m. If the
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Answer:
Step-by-step explanation:
It is given that
Diameter of one pillar = 50cm = 0.5m
So the radius of one pillar = 0.5/2 = 0.25m
Height of one pillar = 4m
We know that the Lateral surface area of one pillar = 2 πrh
By substituting the values
the Lateral surface area of one pillar = 2 × (22/7) × 0.25 × 4
So we get the Lateral surface area of one pillar = 6.285 m²
So the lateral surface area of 20 pillars = 20 × 6.285 = 125.714 m²
It is given that the cost of cleaning = ₹ 14 per m²
So the cost of cleaning 125.714 m2 = ₹ (14 × 125.714)
We get the Cost of cleaning 125.714 m2 = ₹ 1760
Therefore, the cost of cleaning 125.714 m2 is ₹ 1760.
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Diameter of one pillar = 50cm = 0.5m So the radius of one pillar = 0.5/2 = 0.25m Height of one pillar = 4m We know that Lateral surface area of one pillar = 2 πrh By substituting the values Lateral surface area of one pillar = 2 × (22/7) × 0.25 × 4 So we get Lateral surface area of one pillar = 6.285 m2 So the lateral surface area of 20 pillars = 20 × 6.285 = 125.714 m2 It is given that the cost of cleaning = ₹ 14 per m2 So the cost of cleaning 125.714 m2 = ₹ (14 × 125.714) We get Cost of cleaning 125.714 m2 = ₹ 1760 Therefore, the cost of cleaning 125.714 m2 is ₹ 1760.Read more on Sarthaks.com - https://www.sarthaks.com/721370/there-are-20-cylindrical-pillars-in-a-building-each-having-a-diameter-of-50cm-and-height-4m
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