Question

There are 20 divisions in 4 cm of the main scale. The vernier scale has 10 divisions. The least count of the instrument is (a) 0.05 cm

Answer 1

Answer:

options are not given properly.....

I think answer should be 0.005.

hope it will help you....

Mark it as brainliest answer.....

Answer 2

The required length is 2 cm.

Step-by-step explanation:

Since we have given that

Number of divisions = 20

length = 4 cm

If the number of divisions = 10

So, according to question, we get that

$\dfrac{20}{4}=\dfrac{10}{x}\\\\5=\dfrac{10}{x}\\\\x=\dfrac{10}{5}\\\\x=2\ cm$

Hence, the required length is 2 cm.

# learn more:

A Vernier caliper has 20 divisions on the vernier scale. 1 cm on the main scale is divided into 20 equal parts. Find the least count of of this instrument.

https://brainly.in/question/6491403