there are 20 tickets in a box,bearing only one number from 1 to 20 on each.
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We have
Probability of drawing a ticket bearing number 15 is 201
Probability of drawing a ticket bearing a number less than or equal to 15 is 2015=43
∴ Required Probability =Probability of drawing one ticket bearing number 15 and three tickets bearing numbers less than or equal to 15
=4C1×201×(43)3=32027
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