Question

there are 200 pens in a box if 20 are defective and if one pen is taken out randomly then what is the probability of it not being defective​

Answer 1

Answer:

n(s) : 200

no of non defective pen : 200-20=180

n(e) : 180

p(e)=n(e)/n(s)

p(e)=180/200

p(e)=0.9

Answer 2

Answer:

1/180

Step-by-step explanation:

20 pens are defective

So, 200-20=180

Therefore the probability is

1/180 to get a pen which is not defective.

Hope it will help you:D