Question

There are 21 girls in a queue including Saisha.The number of children behind Saisha is four times the number of children ahead her.What is Saisha's position in the queue?

Answer 1

Answer:

Saisha's position in the queue is 5th.

Step-by-step explanation:

Let,

there are a number of students ahead Saisha. And due to this, position of Saisha should be ( a + 1 )th.

Here,

The number of children behind Saisha is four times the number of children ahead her.

Total number of girls is 21.

= > Number of girls behind Saisha = four times of the number of girls ahead Saisha.

= > Number of girls behind Saisha = 4 x a

= > Number of girls behind Saisha = 4a

Then,

= > Total number of girls = 21

= > Number of girls ahead Saisha + 1( that's Saisha ) + number of girls behind Saisha = 21

= > a + 1 + 4a = 21

= > 5a + 1 = 21

= > 5a = 21 - 1

= > 5a = 20

= > a = 20 / 5

= > a = 4

Hence the present position of Saisha is ( a + 1 )th i.e. ( 4 + 1 )th i.e. 5th.

Answer 2

$\mathsf{\huge{\red{\boxed{Answer=4}}}}$

Step-by-step explanation:-

#Heya Mate#

_______________:-)______________

Given :-

Number of children behind saisha=4a

Saisha's Place =a+1

Number of girls = 20

A.T.Q :-

a+1+4a=21

5a+1=21

5a=21-1

5a=20

$a = \frac{20}{5} \\ \\ a = 4$

So,The Sasha's position is 4the

_______________:-)______________

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