There are 24 balls in a pot. If 3 of them are Red, 5 of them are Blue and the remaining
f picking out (i) a Blue ball, (ii) a Red ball
are Green then, what is the probability of picking out (1) a blue bal
and (iii) a Green ball?
Answers
Answered by
8
Step-by-step explanation:
n of S=24
n of red or R=3
P of A=n of R/n of S
= 3/24
=1/8
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