There are 24 eqally spaced points lying on circumference of a circle. what is the maximum number of equilateral triangles that can be drawn by taking sets of three points as the vertices?
Answers
Answered by
7
A whole circle = 360 degrees
Each of the 24 points subtend an angle at the centre of the circle = 360/24
= 15 degrees
Two consecutive vertices of an equilateral triangle subtend and angle of 120 degrees at the centre
Number of possible triangles = 120/15
= 8
There are 8 possible triangles that can be made
Each of the 24 points subtend an angle at the centre of the circle = 360/24
= 15 degrees
Two consecutive vertices of an equilateral triangle subtend and angle of 120 degrees at the centre
Number of possible triangles = 120/15
= 8
There are 8 possible triangles that can be made
Similar questions