Question

There are 24 Letters in the Greek Alphabet. How many fraternity and sorority names can be formed if the names can be 2 or 3 digits long, and repeat of the letters is permitted? (5 marks)
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Answer 1

Permutations nPr

P(n,r)= n! / (n−r)! =?

if the names can be 2 digits long

n = 24

r = 2

P(n,r)= 24 ! / (24-2)! = 552

also repeat of the letters , so (552 + 24) = 576

if the names can be 3 digits long

n = 24

r = 3

P(n,r)= 24 ! / (24-3)! = 12144

also repeat of the letters , so (12144 + 24) = 12168