Question

there are 24 peaches, 36 apricots and 60 bananas and they have to arranged in several rows in such a way that every rows contains the sane member of fruits of only one type. What is the minimum number of rows required for this to happen ?
Options are -
a) 13
b) 9
c) 10
d) 14 ​

Answer 1

Answer:

13 will be the answer

Step-by-step explanation:

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Answer 2

Answer:

Option - (c) 10

Minimum number of rows = Maximum number of fruits in each row

∴ HCF of 24, 36 and 60 = 12

∴ Minimum number of rows = 24 /12+ 36/12+ 60/12

Hence ,

Minimum number of rows = 2 + 3 + 5 = 10