Question

There are 25 chocolates of different flavour in one box . Out of 25 chocolates, 9 are KitKat,10 are of munch and remaining are dairy milk. One student had drawn a chocolate randomly. Find the probability
of getting neither munch nor KitKat.
9/25

8/25

6/25

19/25

Answer 1

Answer:

6/25 is the answer hope it will help you

Answer 2

The probability of getting neither munch nor KitKat is 6/25.

Option (3) is correct.

Given:

• There are 25 chocolates of different flavour in one box .
• Out of 25 chocolates, 9 are KitKat,10 are of munch and remaining are dairy milk.
• One student had drawn a chocolate randomly.

To find:

• Find the probability of getting neither munch nor KitKat.

1. 9/25
2. 8/25
3. 6/25
4. 19/25

Solution:

Formula to be used:

Probability of an event P(E)=Favourable outcomes/Total number of outcomes

Step 1:

Find favourable outcomes for neither munch nor KitKat to be drawn.

As there are

KitKat = 9

Munch = 10

So,

Favourable cases for neither Munch nor KitKat are=$25 - 9 - 10$

or

$= 25 - 19$

or

Favourable cases for neither Munch nor KitKat are$= 6$

Step 2:

Write total outcomes.

Total outcomes are :25

Step 3:

Find Probability of getting neither munch nor KitKat.

Let the probability of this event is P(E).

$\bf P(E) = \frac{6}{25}$

Thus,

Option (3) is correct.

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