There are 25 persons in a tent which is conical in shape. Every person needs an area of 4 sq.m. of the ground inside the tent. If height of the tent is 18m, find the volume of the tent.
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39
Given that the total number of persons in a tent = 25.
Given that every person needs an area of 4sq.m.
![= \ \textgreater \ \pi r^2 = 4 * 25 = \ \textgreater \ \pi r^2 = 4 * 25](https://tex.z-dn.net/?f=%3D+%5C+%5Ctextgreater+%5C+%5Cpi+r%5E2+%3D+4+%2A+25)
![= \ \textgreater \ \pi r^2 = 100 = \ \textgreater \ \pi r^2 = 100](https://tex.z-dn.net/?f=%3D+%5C+%5Ctextgreater+%5C+%5Cpi+r%5E2+%3D+100)
Given the height of the tent = 18m.
The volume of the tent:
![= \ \textgreater \ \frac{1}{3} \pi r^2 h = \ \textgreater \ \frac{1}{3} \pi r^2 h](https://tex.z-dn.net/?f=%3D+%5C+%5Ctextgreater+%5C+++%5Cfrac%7B1%7D%7B3%7D++%5Cpi+r%5E2+h)
![= \ \textgreater \ \frac{1}{3} * 100 * 18 = \ \textgreater \ \frac{1}{3} * 100 * 18](https://tex.z-dn.net/?f=%3D+%5C+%5Ctextgreater+%5C+++%5Cfrac%7B1%7D%7B3%7D+%2A++100+%2A+18)
![= \ \textgreater \ 6 * 100 = \ \textgreater \ 6 * 100](https://tex.z-dn.net/?f=%3D+%5C+%5Ctextgreater+%5C++6+%2A+100)
![= \ \textgreater \ 600m^3 = \ \textgreater \ 600m^3](https://tex.z-dn.net/?f=%3D+%5C+%5Ctextgreater+%5C++600m%5E3)
Therefore, the volume of the tent = 600m^3.
Hope it helps!
Given that every person needs an area of 4sq.m.
Given the height of the tent = 18m.
The volume of the tent:
Therefore, the volume of the tent = 600m^3.
Hope it helps!
siddhartharao77:
:-)
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0
Answer:
Given that the total number of persons in a tent = 25.
Given that every person needs an area of 4sq.m.
= \ \textgreater \ \pi r^2 = 4 * 25= \textgreater πr
2
=4∗25
= \ \textgreater \ \pi r^2 = 100= \textgreater πr
2
=100
Given the height of the tent = 18m.
The volume of the tent:
= \ \textgreater \ \frac{1}{3} \pi r^2 h= \textgreater
3
1
πr
2
h
= \ \textgreater \ \frac{1}{3} * 100 * 18= \textgreater
3
1
∗100∗18
= \ \textgreater \ 600m^3= \textgreater 600m
3
Therefore, the volume of the tent = 600m^3.
Hope it helps!
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