There are 25 workers in the first unit and there are total 8 units. If there are 4 more
workers in each unit than the previous one, then average workers in each unit will
be?
Answers
Answered by
1
a1 = 25, a2 = 29 ....... up to a8.
using arithmetic progression,
first term, a1 = 25,
total term, n = 8,
common difference, d = 4
sum of terms = (n/2){ 2 × a1 + (n - 1)d}
= (8/2){2×25 + (8 - 1)×4}
= 4 { 50 + 28 }
= 4 × 78
so, total workers in all 8 units = 4 × 78
so, avg no of workers = 4×78/8 = 39 ... ans...
Answered by
0
Answer:
please check your solution again
Step-by-step explanation:
series is: 25,29,29,29,29,29,29,29
average=(25+29+29+29+29+29+29+29)/8
=57/2
=28.5
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