There are 26 goats...u have to keep them in 5 cages. Each cage should have only odd numbers..
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It's impossible since the sum of an odd number of odd numbers is always odd.
Consider this:
3 * 2 = 6 (3 + 3; 3 was added twice, so it's even, multiplication by two)
3 * 3 = 9 (3 + 3 + 3; 3 was added thrice, so it's odd)
Consider this:
3 * 2 = 6 (3 + 3; 3 was added twice, so it's even, multiplication by two)
3 * 3 = 9 (3 + 3 + 3; 3 was added thrice, so it's odd)
aryan02p3jd6e:
So are there no constraints about cages inside cages?
what
no
But then it's impossible
Because 5 is odd
And the sum of an odd number of odd terms is always odd
But 26 is even
Let a + b + c + d + e = 26
Where a, b, c, d and e are natural numbers
Then, at least one of them has to be even since 5 is odd and the number of terms is 5
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