Math, asked by alishi6154, 11 months ago

There are 270 ginger chocolates 384milk chocolate and 584coconut chocolates what is the largest number of containers possible so that each container contains the same number of chocolates of each kind

Answers

Answered by slicergiza
0

The largest number of possible containers would be 619.

Step-by-step explanation:

Given,

Ginger chocolates = 270,

Milk chocolates = 384,

Coconut chocolates = 584,

∵ 270 = 2 × 3 × 3 × 3 × 5,

384 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3,

584 = 2 × 2 × 2 × 73,

HCF(270, 384, 584) = 2,

∴ Each container contains 2 chocolates.

Hence, the largest number of possible containers = \frac{270}{2}+\frac{384}{2}+\frac{584}{2}

= 135 + 192 + 292

= 619

#Learn more :

George have 45 packets of chocolate . each packet contains 20 chocolate. 10 packets he sold. how many chocolates are left with him?

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