Question

There are 3 books of mathematics, 4 of science and 5 of literature. Then,
The different collections to be made such that each collection consists of one book of each subject is
1)60
2) 80
3) 100
4) 120
The different collections to be made such that each collection consists of at least
one book of each subject is
1) 3125
2) 3255
3) 3455
4) 4225



please solve with full solution ​

Answer 1

Answer:

(i)

3

C

1

x

4

C

1

x

5

C

1

= 3.4.5 = 60

(ii) (2

3

−1) (2

4

−1) (2

5

−1) = 7 x 15 x 31 = 3255

(iii) 2

3

. 2

4

.(2

5

−1) = 8 x 16 x 31 = 3968.

Step-by-step explanation:

hope it will help you ❤️

Answer 2

$\huge\fbox\red{A}\huge\fbox\pink{N}\fbox\green{S}\huge\fbox\blue{W}\fbox\orange{E}\huge\fbox\red{R}$

M=3,P=4,E=5

a)3C1⋅4C1⋅5C1=60

3)3C0+3C1+..3C3=1+3+3+1=8

8(4C0+4C1+4C2+4C3+4C4)

8⋅16=144

Total=128(5C1+5C2+5C3+5C4+5C5)

=128(5+10+10+5+1) =3468

2)M=3C1+3C2+3C3=3+3+1=7

P=4C1+4C2+4C3+4C4=4+6+4+1=15

E=31

Ways=31*15*7=3255