Question

There are 3 boxes, each of them have equal coins filled, but the weight of one box is more. You can Weigh only one box on the weighing machine, tell how to find the more weighted box?
Its a tricky question, I will give you 99 points, but correct answer only

Answer 1

hey

here is answer




you pick the coins from the boxes  in the following order :-

1 coin from box 1
2 coin from box 2
3 coin from box 3

Now, weigh the total p
coins and let the weight be x grams.
The difference in the weight  = 

let total weight=y grams

(x-y)grams.

Therefore, the box in which that more weight of would be (x-y)/1


and

less weight

= x-y/3


hope it helps

thanks

Answer 2

$\underline{\underline{\Huge\mathfrak{Answer ;}}}$

Here's Your Answer ⏬

=≈≈≈===≈≈≈≈≈===≈≈≈≈≈=≈≈=
Step by Step Explanation ;-
=≈≈≈===≈≈≈≈≈===≈≈≈≈≈=≈≈=

• You are required to pick the coins from the boxes as per the instructed ways ;-

• 1 Coin from Box 1.
• 2 Coins from Box 2.
• 3 Coins from Box 3.

_________________________

• Now , weight the given ( p ) number of coins and let the weight by "y" gm and the Total weight as "q" gm.

=> Now , { y - q } gm.

=> So , the Box having more weight will be ( y - q ) / 1 and the the Box having less weight will be ( y - q ) / 3.


_____________________________

- Regards
@dmohit432