Question

There are 3 bulbs in a box in which 3 bulbs are bad. Find out the probability of removing bad bulbs from the box.​

Answer 1

Answer:

The answer will be 1

Step-by-step explanation: see first,

                      It is given that, there r 3 bulb and that r all bad.

                        so, in this question it is asked that to fine bad bulb.

                          Total bulb=3 and bad bulb=3

                            Now, by  dividing these, i.e.=3/3=1

Answer 2

Step-by-step explanation:

Total good bulbs = 0

Total bad bulbs = 3

Therefore the probability of removing bad bulbs would be $\frac{3}{3}$ or 100$^./^.$