Question

There are 3 cinema house where two type of ticket is sold i.e.
Silver and Gold. Number of Silver ticekt sold by C is 120

more than the numbr of Gold ticket sold by A. Ratio between
number of gold ticket and silver ticket sold by B is 27:35.
Totla number of ticket sold by A is 1000 which is equals to
total numbe of ticket sold by C. It is also given that total
number of silver ticket sold by all the cinema house is 1470. It
is also know that Total number of Gold ticket sold by A and B
is 700​

Answer 1

Answer: i am giving you a gentle advice. don't put math questions. know one will answer it will be a loss of your points.

Remainder: This is not for insulting you or math. Just for telling about the condition in here.

Answer 2

The correct question: There are 3 cinema house where two type of ticket is sold i.e. Silver and Gold. Number of Silver ticket sold by C is 120 more than the number of Gold ticket sold by A. Ratio between number of gold ticket and silver ticket sold by B is 27 : 35. Total number of ticket sold by A is 1000 which is equals to total number of ticket sold by C. It is also given that total number of silver ticket sold by all the cinema house is 1470. It is also know that total number of Gold ticket sold by A and B is 700​.

Find the ratio between Gold tickets sold by C to Silver ticket sold by B cinema house?

a. 9:7

b. 7:9

c. 1:2

d. 3:2.

The correct answer is option (a). 9:7.

Given:

The number of Silver ticket sold by C is 120 more than the number of Gold ticket sold by A.

The ratio between number of gold ticket and silver ticket sold by B = 27:35.

The total number of ticket sold by A = The total number of ticket sold by C = 1000.

The total number of silver ticket sold by all the cinema house = 1470.

The total number of Gold ticket sold by A and B = 700​.

To Find:

We have to find the ratio between Gold tickets sold by C to Silver ticket sold by B cinema house.

Solution:

Let the number of Gold tickets sold by A be x.

∴, The number of the Silver tickets sold by A = (Total number of tickets sold by A) - x = $1000 - x.$

Given that the number of Silver ticket sold by C is 120 more than the number of Gold ticket sold by A.

∴, The number of the Silver tickets sold by C = $x + 120.$

Also, the number of the Gold tickets sold by C = $1000 - (x + 120) = 1000 - x - 120.$

The ratio between number of gold ticket and silver ticket sold by B = 27:35.

From the above ratio, we get,

The number of the Gold tickets sold by B = $27y.$

The number of the Silver tickets sold by B = $35y.$

The total number of silver ticket sold by all the cinema house = 1470.

$i.e., (1000-x) + 35y + (x + 120) = 1470$

Or, $35 y = 1470 - 1000 - 120 = 350.$

On rearranging the above equation, we get,

$y = \frac{350}{35} = 10.$

The total number of Gold ticket sold by A and B = 700​.

∴, $x + 27y = 700.$

Substituting the value of y in the above equation, we get,

$x = \frac{700}{270} = 430.$

We have to find the ratio between Gold tickets sold by C to Silver ticket sold by B cinema house.

Using the values of x and y, the number of gold tickets sold by C and the number of Silver tickets sold by B are,

The number of gold tickets sold by C $= 1000 - x - 120$

$= 1000 - 430 - 120 = 450.$

The number of Silver tickets sold by B $= 35 y = 35$ × $10 = 350.$

∴, The ratio between Gold tickets sold by C to Silver ticket sold by B cinema house = $\frac{number of gold tickets sold by C}{number of silver tickets sold by B}$ $= \frac{450}{350} = \frac{9}{7} .$

Hence, the ratio between Gold tickets sold by C to Silver ticket sold by B cinema house is 9:7.

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