Question

There are 3 consecutive positive integers such that square of middle term increased by the product of other two gives 199.Find the integers

Answer 1

Hey,
Thanks for asking this question.

Lets suppose that the first integer number among three consecutive positive integer is x.

First integer number = x
=> Second integer number = x+1
=> Third integer number = x+2

According to the question,
Square of middle number is increased by the product of other two numbers to give 199.

=> (x+1)^2 + (x)(x+2) = 199
=> x^2 + 2x + 1 + x^2 + 2x = 199
=> 2(x)^2 +4x - 198 = 0
=> x^ + 2x - 99 = 0
=> x^2 + 11x - 9x - 99 = 0
=> x(x+11) -9(x+11) = 0
=> x=9 or x=-11

But since x is a positive integer,it can not be negative.

●So three consecutive numbers are 9,10,11.

●●●Hope My Answer Helped.

Answer 2

Answer:

9,10,11

Step-by-step explanation:

answer is 9,10,11 solution explained above by other person