Math, asked by prathamesh68, 1 year ago

There are 3 economists, 4 engineers, 2 statisticians and I actuary. A committee of 4 from
among them is to be formed. Find the probability that the committee (1) consists of one
professional of each kind; (ii) has at least one economist; (iii) has the actuary as a member and
three others; (iv) has at least one engineer but no economist.​

Answers

Answered by amitnrw
23

Different probabilities of Forming a committe of Economist , Engineers , statisticians and Actuary calculated

Step-by-step explanation:

There are 3 economists, 4 engineers, 2 statisticians and I actuary.

Total 10

A committee of 10 can be formed in ¹⁰C₄  ways

= 210 Ways

consists of one professional of each  = 3 * 4 * 2 * 1 = 24 Ways

Probability = 24/210  = 4/35

(ii) has at least one economist;  

1 economist  , 2 economist , 3 economist

1 economist =³C₁  *  ⁷C₃  = 105

2 economist = ³C₂ * ⁷C₂  = 63

3 economist = ³C₃ * ⁷C₁  = 7

= 175

Probability = 175/210 = 5/6

(iii) has the actuary as a member and three others =  1 * ⁹C₃  = 84  ways

Probability = 84/210 = 14/35

(iv) has at least one engineer but no economist.​

if no economist then total possibilities = ⁷C₄ = 35

if no engineer also then ⁴C₀ * ³C₄  ( not possible)

so all 35 cases will have atleast 1 engineer if no economist

Probability =  35/210 = 1/6

Answered by nakshathranambiar200
0

Answer:

1/6

Step-by-step explanation:

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