Question

There are 3 identical cups. 1st cup has 50% water, 2nd cup has 25% water and 3rd cup has 25% water. What percentage of water do i need to remove from the 1st cup and pour into the other two cups to make the level of water in all the three cups same

Answer 1

Answer:

25 25 percentage

Step-by-step explanation:

how if u pour half 25 and 25 per in 2nd and 3rd it will 50 and 50 percentage same both

Answer 2

Answer:

$16\frac{2}{3}\%$

Step-by-step explanation:

Given,

In 3 identical cups,

Water in 1st cup = 50%,

Water in 2nd cup = 25%,

Water in 3rd cup = 25%,

So, the average percentage of water in a cup

$=\frac{50+25+25}{3}$

$=\frac{100}{3}\%$

Thus, Each cup has $\frac{100}{3}\%$ water after removing water from 1st cup and pouring it to second and third cup,

Now, the change in water percentage in 1st cup =

$\frac{100}{3}\% - 50\% = \frac{100-150}{3}=-\frac{50}{3}\% = -16\frac{2}{3}\%$

Hence, we need to remove $16\frac{2}{3}\%$ of water from the 1st cup.