There are 3 identical cups. 1st cup has 50% water, 2nd cup has 25% water and 3rd cup has 25% water. What percentage of water do i need to remove from the 1st cup and pour into the other two cups to make the level of water in all the three cups same.
Answers
Answer:
16⅔%
Step-by-step explanation:
In this question we need to get the average percentage for the three cups.
The average percentage is given by :
(50% + 25% + 25%) / 3 = 100%/3 = 33⅓%
Each cup should have 33⅓% for the cups to have equal amounts of water.
Therefore the amount that should be removed from the first cup and distributed to the other two cups is :
50% - 33⅓% = 16 ⅔%
We therefore remove 16⅔% of water from the first jar.
Answer:
33.33 %
16.66%
Step-by-step explanation:
Let say capacity of each cup = 24x
First cup has 50 % water = (50/100)24x = 12x
Second cup has = (25/100)* 24x = 6x
Third cup has = 6x
To have water equal in each cup
water in each cup = 24x/3 = 8x
Water to be removed from Cup1 = 12x - 8x = 4x
% of water removed from cup 1 = (4x/12x)* 100 = 33.33 %
in term of total water , % to be removed = (4x/24x) * 100 = 16.66%