Question

There are 3 identical yellow balls and 4 identical blue balls. they are arranged in a straight line. what is the probability that neither of the yellow balls are at the extreme ends of the arrangements?

Answer 1

This is the right answer

Answer 2

Answer:

The probability that neither of the yellow balls are at the extreme ends of the arrangements is 4.

Step-by-step explanation:

3 yellow balls and 4 blue balls.

Step 1:

Total outcome=3 yellow balls + 4 blue balls => 7 balls.

Number of non yellow balls = 4

Step 2:

First lets we need to find the number of ways they can be arrange in a row. Combination can be given as follows:  

3 yellow balls and 4 blue balls = 12! / 5! 4! 3! = 36  

Step 3:

That is the combination 4C2 can be expand as $\frac{12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 4 \times 3 \times 2 \times 1 \times 3 \times 2 \times 1}$  = 110 x 252 =27720.