Question

there are 3 number these are co prime to each other are such that the product of frist two is 399 and that of the last two is 525​

Answer 1

Answer:

Your answer is this

All three numbers are co-prime to each other, So the common factor is 1.

Product of the first two numbers=551

Product of the last two numbers=1073

HCF of  551 and1073 is the middle number.

Middle number,HCF(551,1073)=29

First number=29551​

                     =19

Last number =291073​

                      =37

Sum of the three numbers =19+29+37=85

Step-by-step explanation:

Answer 2

Answer:

Sum of the numbers is =(19+21+25)= 65

Step-by-step explanation:

middle number = H.C.F. of 399 and 525= 21;

so first number is : 399/21= 19

Third numberb=525/21=25

Sum of the numbers is =(19+21+25)=65