Question

There are 3 persons namely A, B and C in a family. The average a
A and B is 20, the average age of B and C is 19, and the average
Cand A is 21. The ages of A, B and C are​

Answer 1

Answer:

AtQ

average age of A and B is 20 years

average age of B and C is 19 years

average age of C and A is 21 years

then,

let the age of A, B andC are x, y, z respectively

then,

(x + y )/2 =20

x + y = 20 *2 =40 (1)

now,

(y + z)/2 =19

y +z =19*2 =38 (2)

now,

(z + x ) \ 2 = 21

z + x= 21*2 = 42 (3)

on adding (1) &(3)

x +y + (z+x) =40+42

2x + y + z = 82

2x + 38 = 82 (from 2)

2x = 82-38

x= 44/2

x = 22 years

now,

x +y =40

22 + y =40

y =40-22 =18 years

now,

y + z= 38

18 + z = 38

z = 38-18

z =20 years

therfore,

A =22years

B = 18 years

C= 20 years