There are 3 red, 5 blue and 2 yellow balls in a box. Two balls are drawn at random without replacing the first one. Find the probability that i) at least one is yellow ii) both of them are not red
Answers
Answered by
0
Total number of balls = 3 red + 5 blue + 2 yellow ===> 10 balls
Two balls randomly drawn out from a box without replacing the 1st one
(i i) Event :- Both of them are not red
Probability that both are not red P = p( E ) / n (s)
7/10
Two balls randomly drawn out from a box without replacing the 1st one
(i i) Event :- Both of them are not red
Probability that both are not red P = p( E ) / n (s)
7/10
Similar questions
Math,
7 months ago
Business Studies,
7 months ago
Science,
7 months ago
Physics,
1 year ago
Hindi,
1 year ago