There are 3 red, 5 blue and 2 yellow balls in a box. Two balls are drawn at random without replacing the first one. Find the probability that i) at least one is yellow ii) both of them are not red
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Total number of balls = 3 red + 5 blue + 2 yellow ===> 10 balls
Two balls randomly drawn out from a box without replacing the 1st one
(i i) Event :- Both of them are not red
Probability that both are not red P = p( E ) / n (s)
7/10
Two balls randomly drawn out from a box without replacing the 1st one
(i i) Event :- Both of them are not red
Probability that both are not red P = p( E ) / n (s)
7/10
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