There are 3 red balls,4 green balls and 7 blue balls.a person picks a random ball out of the bag.find the probability that it is neither green nor red
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total outcomes= 3+4+7=14
fav .outcome= 14-(3+4)=7
pro.= 7/14=1/2
fav .outcome= 14-(3+4)=7
pro.= 7/14=1/2
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total ball =3+4+7=14
ball which is neither green nor red=7blue ball
Probability =favourable quantity/total quantity
p(of getting ball which is neither green nor red)=7/14
=1/2
HOPE IT HELP U PLZ ADD IT AS BRANLIST
ball which is neither green nor red=7blue ball
Probability =favourable quantity/total quantity
p(of getting ball which is neither green nor red)=7/14
=1/2
HOPE IT HELP U PLZ ADD IT AS BRANLIST
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