There are 3 rows containing 2 seats in each row the number of ways in which 3 persons can be seated such that no row remains empty is
Answers
Given: 3 rows containing 2 seats in each row
To Find : number of ways in which 3 persons can be seated such that no row remains empty is
Solution:
There are 3 rows containing 2 seats in each row
Persons = 3
no row remains empty
Hence one person in one row
3 Person for 3 rows can be selected in ³C₃ = 3! = 6 ways
in Each row person can seat in 2 Ways
Hence total ways = 2 x 2 x 2 x 6 = 48
48 ways , 3 persons can be seated such that no row remains empty
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