Question

There are 3 tailors - A, B and C who can each stitch a shirt in 1 hr, 1 hr 30 min and 2 hr respectively. If there is an order of 150 shirts, in how many hours can they execute the order working
together? Any shirt is worked on only by one of the tailors, i.e., two or more tailors do not work on the same shirt.​

Answer 1

Answer:

I think its 900/13 hrs.

Step-by-step explanation:

Answer 2

Given: A, B and C who can each stitch a shirt in 1 hr, 1 hr 30 min and 2 hr respectively.

Total number of shirts ordered$=150$

To find: the number of hours required to complete the order.

Solution:

Take LCM of $1, 1.5, 2$.

$\[LCM\left( {1,1.5,2} \right) = 3\]$

Therefore, the LCM will be 3.

Observe that,

A stitches 6 shirts in 6 hrs

B stitches 4 shirs in 6 hrs

C stitches 3 shirts in 6 hrs,

Understand that,  

6 hrs are required to make 13 shirts.

Therefore,  

In 66 hrs, 143 shirts will be made and 7 shirts more are required to be made,

Know that,

Tailor A will make 3 shirts in 3 hrs

Tailor B will make 2 shirts in 3 hrs

Tailor c will make 1.5 shirts in 3 hrs, then Tailor C will take 1 hr more to complete$\frac{1}{2}$ shirt.

Find the total time taken to by all three to complete 150 shirts.

Total time taken by all three to complete 7 shirts $= 4 hr$

Total time taken to complete 150 shirts$= 66+4$

                                                                $=70$