Question

There are 30 cards numbered from 1 to 30. One card is drawn at random. Find the probability of getting the card with
a), a two-digit number
b). a perfect square number
c), a number divisible by 5.
d) a number divisible by 2 or 3.
e), a number divisible by 2 and 3.
n. a number divisible by 7.
g). a number multiple of 8.
h). a two digit number divisible by 5.
i). a two digit number divisible by 2.
J). a two digit number divisible by 3.

plz...answer this question I'll mark u as brainlyest...​

Answer 1

Answer:

Step-by-step explanation:

a. there will be 21 numbers with two digits 10 to 30 so the probability is 21/30=7/10

b. perfect squares are 4,9,16,25=4/30=2/15

c. divisible by 5={5,10,15,20,25,30}=6/30=1/5

d. divisible by 2={2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}=15/30=1/2

divisible by 3={3,6,9,12,15,18,24,21,27,30}=10/30=1/3

1/2+1/3=5/6

e. 6,12,18,24,30=5/30=1/6

f. 7,14,21,28=4/30=2/15

g. 8,16,24=3/30=1/10

h. 5/30=1/6

i. 11/30

j. 7/30

Answer 2

Answer:

a) 21/30

b) 4/30

c) 6/30

d) 20/30

e) 5/30

f) 4/30

g) 3/30

h) 5/30

i) 11/30

j) 7/30