Question

There are 30 cards of the same size in a bag in which the numbers 1 to 30 are
written. One card is taken out from the bag at random. Find the probability
that the number on the selected card is not divisible by 3​

Answer 1

Answer:

Step-by-step explanation:

Total no. of possible outcomes = 30 {1, 2, 3, … 30} E ⟶ event of getting no. divisible by 3. No. of favourable outcomes = 10 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30} Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) P(E) = 10/30 = 1/3 Bar E ⟶ event of getting no. not divisible by 3. P(Bar E) = 1 – P(E) = 1 - 1/3 = 2/3Read more on Sarthaks.com - https://www.sarthaks.com/102426/there-are-cards-same-size-bag-on-which-numbers-are-written-one-card-taken-out-the-bag-random

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Answer 2

Answer:

no. of cards divisible by 3 = 10

implies no. I

of cards not divisible by 3 = 20

hence P(card not divisible by 3)=20/30=2/3