Question

there are 300 fish in a pond. The fish population is increasing by approximately 15% per year.

Enter an equation that can be used to find the amount of fish in the pond, y, after 6 years.

Answer 1

$Number \: of \: fish \: in \: a \:pond \: intially (P)\\= 300$

$Increase \: fish \: population (r) = 15\% \: p.a$

$Time (T) = 6\: years$

$Conversion \:period (n) = 6$

$Amount \:of \:fish \: after\:6 \:years (A) \\= P\Big( 1 + \frac{r}{100}\Big)^{n}$

$= 300\Big( 1 + \frac{15}{100}\Big)^{6}$

$= 300\Big(1+ \frac{3}{20}\Big)^{6} \\= 300 \times \Big(\frac{23}{20}\Big)^{6} \\= 693.9 \approx 693$

Therefore.,

$\red{Amount \:of \:fish \: after\:6 \:years}\\\green { = 693 }$

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