Math, asked by mbilal123au, 1 year ago

There Are 35 Student in art class and 57 in Dance Class find the number of students who are either in dance class or art class
. when Classes meet at different hours 12 students are enrolled in both activities
.when two classes met at same hour

Answers

Answered by ommishra5773
79

Answer:

60

Step-by-step explanation:

no. of students in art class =35

no. of students in dance class =57

no. of students in all=35+57

35

+57

= 82

then no. of students were out =

12

Now do it (82-12=?)

82

- 12

=70

and is=70

Answered by amitnrw
228

Given : 35 Student in art class and 57 in Dance Class  . 12 students are enrolled in both activities

To find : the number of students who are either in dance class or art class

Solution:

Number of Students in Art Class  n(A) = 35

Number of Students in Dance class  n(D) = 57

Number of Students in Art & Dance class Both n(A∩D) = 12

number of students who are either in dance class or art class = n( A U D)

n( A U D)  = n(A) +  n(D)  -  n(A∩D)

=> n( A U D)  = 35 + 57 - 12

=> n( A U D)  = 92 - 12

=> n( A U D)  = 80

80  number of students who are either in dance class or art class

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