There Are 35 Student in art class and 57 in Dance Class find the number of students who are either in dance class or art class
. when Classes meet at different hours 12 students are enrolled in both activities
.when two classes met at same hour
Answers
Answer:
60
Step-by-step explanation:
no. of students in art class =35
no. of students in dance class =57
no. of students in all=35+57
35
+57
= 82
then no. of students were out =
12
Now do it (82-12=?)
82
- 12
=70
and is=70
Given : 35 Student in art class and 57 in Dance Class . 12 students are enrolled in both activities
To find : the number of students who are either in dance class or art class
Solution:
Number of Students in Art Class n(A) = 35
Number of Students in Dance class n(D) = 57
Number of Students in Art & Dance class Both n(A∩D) = 12
number of students who are either in dance class or art class = n( A U D)
n( A U D) = n(A) + n(D) - n(A∩D)
=> n( A U D) = 35 + 57 - 12
=> n( A U D) = 92 - 12
=> n( A U D) = 80
80 number of students who are either in dance class or art class
Learn more:
Observe the given Venn diagram and write the following sets. (i) A (ii ...
https://brainly.in/question/4557661
If U is the set of all digits in our decimal system,A = {x:x is prime}, B ...
https://brainly.in/question/453045