Math, asked by mbilal123au, 11 months ago

There Are 35 Student in art class and 57 in Dance Class find the number of students who are either in dance class or art class
. when Classes meet at different hours 12 students are enrolled in both activities
.when two classes met at same hour

Answers

Answered by ommishra5773
79

Answer:

60

Step-by-step explanation:

no. of students in art class =35

no. of students in dance class =57

no. of students in all=35+57

35

+57

= 82

then no. of students were out =

12

Now do it (82-12=?)

82

- 12

=70

and is=70

Answered by amitnrw
228

Given : 35 Student in art class and 57 in Dance Class  . 12 students are enrolled in both activities

To find : the number of students who are either in dance class or art class

Solution:

Number of Students in Art Class  n(A) = 35

Number of Students in Dance class  n(D) = 57

Number of Students in Art & Dance class Both n(A∩D) = 12

number of students who are either in dance class or art class = n( A U D)

n( A U D)  = n(A) +  n(D)  -  n(A∩D)

=> n( A U D)  = 35 + 57 - 12

=> n( A U D)  = 92 - 12

=> n( A U D)  = 80

80  number of students who are either in dance class or art class

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