Question

There are 35 students in the art class and 57 students in the dance class. Find the number of students who are either in the art class or in the dance class when Two classes meet at different hours and 12 students are enrolled in both activities

Answer 1

Given: There are 35 students in the art class and 57 students in the dance class.

To find: The number of students who are either in the art class or in the dance class when Two classes meet at different hours and 12 students are enrolled in both activities.

Solution:

• Now we have given that there are 35 students in the art class and 57 students in the dance class.

• So let the set of students in art class be X and the set of students in dance class be Y.

• So n(X) = 35 and n(Y) = 57

• Now when 2 classes meet at different hours and 12 students are enrolled in both activities we have:

                       n(X U Y) = n(X) + n(Y) - n(X∩Y)

                      n(X U Y) = 35 + 57 - 12

                      n(X U Y) = 92 - 12

                       n(X U Y) = 80

Answer:

                   So the number of students who are either in the art class or in the dance class when two classes meet at different hours and 12 students are enrolled in both activities are 80.