Question

There are 38 coins in a collection of 20 paise coins and 25 paise coins. If the total value of the collection is Rs. 8.50, how many coins of each are there?

Answer 1

Answer:

num of 20p coins be x and 25p coims be y

then

x+y =38........(i)

20x +25y=850...(ii)

20x+25y)-(20x +20 y)=850-760

5y=90

y=18

therefore

x=38-18

x=20

therefore num of 20p coins are 20 and 25p coins are 18

Answer 2

Answer:

18

Step-by-step explanation:

Let the number of 20 paise coins be x

And let the number of 25 paise coins be y.

Then, according to the given conditions we have

x + y = 38 … (i) and

20x + 25y = 850 … (ii) [Since, 8.50 Rs = 850 paise]

Performing (ii) – 20 x (i), we get

20x + 25y = 850

20x + 20y = 760

(-)–(-)—–(-)—–

5y = 90

y = 90/5

y = 18

Substituting the value of y in (i), we have

x + 18 = 38

x = 38 – 18

x = 20

Therefore, the number of 20 paise coins are 20 and the number of 25 paise coins are 18.