There are 38 coins in a collection of 20 paise coins and 25 paise coins. If the total value of the collection is Rs. 8.50. how many of each are there?
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Class 12
>>Applied Mathematics
>>Linear Equations
>>Solving a Pair of Linear Equations - Elimination Method
>>There are 38 coins in a collection of 20
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There are 38 coins in a collection of 20 paise coins and 25 paise coins. If the total value of the collection is Rs. 8.50, how many of each are there?
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Solution
The number of 20 paise coins be x and,
The number of 25 paise coins be y.
Then, according to the given conditions we have
x+y=38 … (i) and
20x+25y=850 … (ii) [Since, 8.50 Rs = 850 paise]
Performing {(ii) −20× (i)}, we get
(20x+25y)−(20x+20y)=850−760
⇒5y=90
⇒y=
5
90
⇒y=18
Substituting the value of y in (i), we have
x+18=38
⇒x=38−18
⇒x=20
Therefore, the number of 20 paise coins are 20 and the number of 25 paise coins are 18.
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