Math, asked by pavanchowdary1682, 1 year ago

There are 4 blue 3 red and 2 black pens in a box they are drawn one by one determine all the different permutations

Answers

Answered by gautam2406
3

Step-by-step explanation:

Total no of pen's=4+3+2=9

Permutation (blue pen)=4/9

Permutation (red pen)=3/9=1/3

Permutation (black pen)=2/9

Answered by sharonr
0

The total number of permutations is 1260

Solution:

Given that,

There are 4 blue 3 red and 2 black pens in a box

Total pens = 4 + 3 + 2 = 9

Blue = 4

Red = 3

Black = 2

The total number of permutations is:

\frac{ 9 ! }{ 4! \times 3 ! \times 2 ! } \\\\\frac{ 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{ 4 \times 3 \times 2 \times 1 \times 3 \times 2 \times 1 \times 2 \times 1 }\\\\\frac{ 9 \times 8 \times 7 \times 6 \times 5 }{12}\\\\ 1260

Thus the total number of permutations is 1260

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