Question

There are 4 blue ball and 6 orange 3brown balls find probability of: (A) orange ball (B) brown ball​

Answer 1

Answer:

n(S)=4+6+3

=13

Let A be the probability of getting orange ball

n(A)=6

p(A)=n(A)/n(S)

=6/13

Let B be the probability of getting brown ball

n(B)=3

p(B)=n(B)/n(S)

=3/13